mangavalkandClaude Opus 5.5
b347f1c63f
Vendored from https://github.com/gpeter62/ESP_UniClock: the sketch source, the web UI and the libraries the ESP8266 build needs, unpacked from the bundled zips. Adds a PlatformIO project for the ESP-12. The source is unchanged; local changes follow as separate commits. Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
60 lines
1.8 KiB
C++
60 lines
1.8 KiB
C++
// ArduinoJson - https://arduinojson.org
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// Copyright © 2014-2022, Benoit BLANCHON
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// MIT License
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//
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// This example shows how to deserialize a JSON document with ArduinoJson.
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#include <iostream>
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#include "ArduinoJson.h"
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int main() {
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// Allocate the JSON document
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//
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// Inside the brackets, 200 is the capacity of the memory pool in bytes.
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// Don't forget to change this value to match your JSON document.
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// Use https://arduinojson.org/v6/assistant to compute the capacity.
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StaticJsonDocument<300> doc;
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// StaticJsonDocument<N> allocates memory on the stack, it can be
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// replaced by DynamicJsonDocument which allocates in the heap.
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//
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// DynamicJsonDocument doc(200);
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// JSON input string.
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//
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// Using a char[], as shown here, enables the "zero-copy" mode. This mode uses
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// the minimal amount of memory because the JsonDocument stores pointers to
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// the input buffer.
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// If you use another type of input, ArduinoJson must copy the strings from
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// the input to the JsonDocument, so you need to increase the capacity of the
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// JsonDocument.
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char json[] =
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"{\"sensor\":\"gps\",\"time\":1351824120,\"data\":[48.756080,2.302038]}";
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// Deserialize the JSON document
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DeserializationError error = deserializeJson(doc, json);
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// Test if parsing succeeds.
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if (error) {
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std::cerr << "deserializeJson() failed: " << error.c_str() << std::endl;
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return 1;
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}
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// Fetch values.
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//
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// Most of the time, you can rely on the implicit casts.
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// In other case, you can do doc["time"].as<long>();
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const char* sensor = doc["sensor"];
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long time = doc["time"];
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double latitude = doc["data"][0];
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double longitude = doc["data"][1];
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// Print values.
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std::cout << sensor << std::endl;
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std::cout << time << std::endl;
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std::cout << latitude << std::endl;
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std::cout << longitude << std::endl;
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return 0;
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}
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